Solve (24*sqrt{9/16}+12divsqrt[3]{64}-(1/10)^-1)^2

$$( 24 \cdot \sqrt { \frac { 9 } { 16 } } + 12 \div \sqrt[ 3 ] { 64 } - ( \frac { 1 } { 10 } ) ^ { - 1 } ) ^ { 2 }$$

Evaluate

$$121$$

Solution Steps

Rewrite the square root of the division \frac{9}{16} as the division of square roots \frac{\sqrt{9}}{\sqrt{16}}. Take the square root of both numerator and denominator.

$$\left(24\times \frac{3}{4}+\frac{12}{\sqrt[3]{64}}-\left(\frac{1}{10}\right)^{-1}\right)^{2}$$

Multiply 24 and \frac{3}{4} to get 18.

$$\left(18+\frac{12}{\sqrt[3]{64}}-\left(\frac{1}{10}\right)^{-1}\right)^{2}$$

Calculate \sqrt[3]{64} and get 4.

$$\left(18+\frac{12}{4}-\left(\frac{1}{10}\right)^{-1}\right)^{2}$$

Divide 12 by 4 to get 3.

$$\left(18+3-\left(\frac{1}{10}\right)^{-1}\right)^{2}$$

Add 18 and 3 to get 21.

$$\left(21-\left(\frac{1}{10}\right)^{-1}\right)^{2}$$

Calculate \frac{1}{10} to the power of -1 and get 10.

$$\left(21-10\right)^{2}$$

Subtract 10 from 21 to get 11.

$$11^{2}$$

Calculate 11 to the power of 2 and get 121.

$$121$$

Factor

$$11^{2}$$