Solve (22+8+5*(18:2)]:3-2*4*(2*6-9)=

$$( 22 + 8 + 5 \times ( 18 : 2 ) ] : 3 - 2 \times 4 \times ( 2 \times 6 - 9 ) =$$

Evaluate

$$1$$

Solution Steps

Add 22 and 8 to get 30.

$$\frac{30+5\times \frac{18}{2}}{3}-2\times 4\left(2\times 6-9\right)$$

Divide 18 by 2 to get 9.

$$\frac{30+5\times 9}{3}-2\times 4\left(2\times 6-9\right)$$

Multiply 5 and 9 to get 45.

$$\frac{30+45}{3}-2\times 4\left(2\times 6-9\right)$$

Add 30 and 45 to get 75.

$$\frac{75}{3}-2\times 4\left(2\times 6-9\right)$$

Divide 75 by 3 to get 25.

$$25-2\times 4\left(2\times 6-9\right)$$

Multiply 2 and 4 to get 8.

$$25-8\left(2\times 6-9\right)$$

Multiply 2 and 6 to get 12.

$$25-8\left(12-9\right)$$

Subtract 9 from 12 to get 3.

$$25-8\times 3$$

Multiply 8 and 3 to get 24.

$$25-24$$

Subtract 24 from 25 to get 1.

$$1$$

Factor

$$1$$