Solve (2,5+42,5+1/25-2)div1/25+1=

$$( 2,5 + \frac { 42,5 + 1 } { 25 - 2 } ) \div \frac { 1 } { 25 } + 1 =$$

Evaluate

$$\frac{2548}{23}\approx 110,782608696$$

Solution Steps

Add 42,5 and 1 to get 43,5.

$$\frac{2,5+\frac{43,5}{25-2}}{\frac{1}{25}}+1$$

Subtract 2 from 25 to get 23.

$$\frac{2,5+\frac{43,5}{23}}{\frac{1}{25}}+1$$

Expand \frac{43,5}{23} by multiplying both numerator and the denominator by 10.

$$\frac{2,5+\frac{435}{230}}{\frac{1}{25}}+1$$

Reduce the fraction \frac{435}{230} to lowest terms by extracting and canceling out 5.

$$\frac{2,5+\frac{87}{46}}{\frac{1}{25}}+1$$

Convert decimal number 2,5 to fraction \frac{25}{10}. Reduce the fraction \frac{25}{10} to lowest terms by extracting and canceling out 5.

$$\frac{\frac{5}{2}+\frac{87}{46}}{\frac{1}{25}}+1$$

Least common multiple of 2 and 46 is 46. Convert \frac{5}{2} and \frac{87}{46} to fractions with denominator 46.

$$\frac{\frac{115}{46}+\frac{87}{46}}{\frac{1}{25}}+1$$

Since \frac{115}{46} and \frac{87}{46} have the same denominator, add them by adding their numerators.

$$\frac{\frac{115+87}{46}}{\frac{1}{25}}+1$$

Add 115 and 87 to get 202.

$$\frac{\frac{202}{46}}{\frac{1}{25}}+1$$

Reduce the fraction \frac{202}{46} to lowest terms by extracting and canceling out 2.

$$\frac{\frac{101}{23}}{\frac{1}{25}}+1$$

Divide \frac{101}{23} by \frac{1}{25} by multiplying \frac{101}{23} by the reciprocal of \frac{1}{25}.

$$\frac{101}{23}\times 25+1$$

Express \frac{101}{23}\times 25 as a single fraction.

$$\frac{101\times 25}{23}+1$$

Multiply 101 and 25 to get 2525.

$$\frac{2525}{23}+1$$

Convert 1 to fraction \frac{23}{23}.

$$\frac{2525}{23}+\frac{23}{23}$$

Since \frac{2525}{23} and \frac{23}{23} have the same denominator, add them by adding their numerators.

$$\frac{2525+23}{23}$$

Add 2525 and 23 to get 2548.

$$\frac{2548}{23}$$

Factor

$$\frac{13 \cdot 2 ^ {2} \cdot 7 ^ {2}}{23} = 110\frac{18}{23} = 110.78260869565217$$