Solve (2y-(3y-4)+5y-6)+10y=(12y-12)+36

$$( 2 y - ( 3 y - 4 ) + 5 y - 6 ) + 10 y = ( 12 y - 12 ) + 36$$

Solve for y

$$y=13$$

Steps for Solving Linear Equation

To find the opposite of 3y-4, find the opposite of each term.

$$2y-3y-\left(-4\right)+5y-6+10y=12y-12+36$$

The opposite of -4 is 4.

$$2y-3y+4+5y-6+10y=12y-12+36$$

Combine 2y and -3y to get -y.

$$-y+4+5y-6+10y=12y-12+36$$

Combine -y and 5y to get 4y.

$$4y+4-6+10y=12y-12+36$$

Subtract 6 from 4 to get -2.

$$4y-2+10y=12y-12+36$$

Combine 4y and 10y to get 14y.

$$14y-2=12y-12+36$$

Add -12 and 36 to get 24.

$$14y-2=12y+24$$

Subtract 12y from both sides.

$$14y-2-12y=24$$

Combine 14y and -12y to get 2y.

$$2y-2=24$$

Add 2 to both sides.

$$2y=24+2$$

Add 24 and 2 to get 26.

$$2y=26$$

Divide both sides by 2.

$$y=\frac{26}{2}$$

Divide 26 by 2 to get 13.

$$y=13$$