Solve (2xy)(3x^2y^3)=

$$( 2 x y ) ( 3 x ^ { 2 } y ^ { 3 } ) =$$

Evaluate

$$6x^{3}y^{4}$$

Steps Using Commutative Property of Multiplication

Use the rules of exponents to simplify the expression.

$$2^{1}x^{1}y^{1}\times 3^{1}x^{2}y^{3}$$

Use the Commutative Property of Multiplication.

$$2^{1}\times 3^{1}x^{1}x^{2}y^{1}y^{3}$$

To multiply powers of the same base, add their exponents.

$$2^{1}\times 3^{1}x^{1+2}y^{1+3}$$

Add the exponents 1 and 2.

$$2^{1}\times 3^{1}x^{3}y^{1+3}$$

Add the exponents 1 and 3.

$$2^{1}\times 3^{1}x^{3}y^{4}$$

Multiply 2 times 3.

$$6x^{3}y^{4}$$

Differentiate w.r.t. x

$$18x^{2}y^{4}$$