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4x^{2}-20x+25=\left(x+3\right)\left(4x-8\right)
Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(2x-5\right)^{2}.
4x^{2}-20x+25=4x^{2}+4x-24
Use the distributive property to multiply x+3 by 4x-8 and combine like terms.
4x^{2}-20x+25-4x^{2}=4x-24
Subtract 4x^{2} from both sides.
-20x+25=4x-24
Combine 4x^{2} and -4x^{2} to get 0.
-20x+25-4x=-24
Subtract 4x from both sides.
-24x+25=-24
Combine -20x and -4x to get -24x.
-24x=-24-25
Subtract 25 from both sides.
-24x=-49
Subtract 25 from -24 to get -49.
x=\frac{-49}{-24}
Divide both sides by -24.
x=\frac{49}{24}
Fraction \frac{-49}{-24} can be simplified to \frac{49}{24} by removing the negative sign from both the numerator and the denominator.