Solve (2x-3y)=(4+x)+(3y-1)

$$( 2 x - 3 y ) = ( 4 + x ) + ( 3 y - 1 )$$

Solve for x

$$x=6y+3$$

Solution Steps

Subtract 1 from 4 to get 3.

$$2x-3y=3+x+3y$$

Subtract x from both sides.

$$2x-3y-x=3+3y$$

Combine 2x and -x to get x.

$$x-3y=3+3y$$

Add 3y to both sides.

$$x=3+3y+3y$$

Combine 3y and 3y to get 6y.

$$x=3+6y$$

Solve for y

$$y=\frac{x-3}{6}$$

Steps for Solving Linear Equation

Subtract 1 from 4 to get 3.

$$2x-3y=3+x+3y$$

Subtract 3y from both sides.

$$2x-3y-3y=3+x$$

Combine -3y and -3y to get -6y.

$$2x-6y=3+x$$

Subtract 2x from both sides.

$$-6y=3+x-2x$$

Combine x and -2x to get -x.

$$-6y=3-x$$

Divide both sides by -6.

$$\frac{-6y}{-6}=\frac{3-x}{-6}$$

Dividing by -6 undoes the multiplication by -6.

$$y=\frac{3-x}{-6}$$

Divide 3-x by -6.

$$y=\frac{x}{6}-\frac{1}{2}$$