Solve (2x-3)^2+4x(x-7)4(-x-2)^3

$$( 2 x - 3 ) ^ { 2 } + 4 x ( x - 7 ) 4 ( - x - 2 ) ^ { 3 }$$

Evaluate

$$16x\left(x-7\right)\left(-x-2\right)^{3}+\left(2x-3\right)^{2}$$

Solution Steps

Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(2x-3\right)^{2}.

$$4x^{2}-12x+9+4x\left(x-7\right)\times 4\left(-x-2\right)^{3}$$

Multiply 4 and 4 to get 16.

$$4x^{2}-12x+9+16x\left(x-7\right)\left(-x-2\right)^{3}$$

Use binomial theorem \left(a-b\right)^{3}=a^{3}-3a^{2}b+3ab^{2}-b^{3} to expand \left(-x-2\right)^{3}.

$$4x^{2}-12x+9+16x\left(x-7\right)\left(\left(-x\right)^{3}-6\left(-x\right)^{2}+12\left(-x\right)-8\right)$$

Calculate -x to the power of 2 and get x^{2}.

$$4x^{2}-12x+9+16x\left(x-7\right)\left(\left(-x\right)^{3}-6x^{2}+12\left(-x\right)-8\right)$$

Use the distributive property to multiply 16x by x-7.

$$4x^{2}-12x+9+\left(16x^{2}-112x\right)\left(\left(-x\right)^{3}-6x^{2}+12\left(-x\right)-8\right)$$

Use the distributive property to multiply 16x^{2}-112x by \left(-x\right)^{3}-6x^{2}+12\left(-x\right)-8.

$$4x^{2}-12x+9+16x^{2}\left(-x\right)^{3}-96x^{4}+192x^{2}\left(-x\right)-128x^{2}-112x\left(-x\right)^{3}+672x^{3}-1344x\left(-x\right)+896x$$

Multiply -1344 and -1 to get 1344.

$$4x^{2}-12x+9+16x^{2}\left(-x\right)^{3}-96x^{4}+192x^{2}\left(-x\right)-128x^{2}-112x\left(-x\right)^{3}+672x^{3}+1344xx+896x$$

Multiply x and x to get x^{2}.

$$4x^{2}-12x+9+16x^{2}\left(-x\right)^{3}-96x^{4}+192x^{2}\left(-x\right)-128x^{2}-112x\left(-x\right)^{3}+672x^{3}+1344x^{2}+896x$$

Combine -128x^{2} and 1344x^{2} to get 1216x^{2}.

$$4x^{2}-12x+9+16x^{2}\left(-x\right)^{3}-96x^{4}+192x^{2}\left(-x\right)+1216x^{2}-112x\left(-x\right)^{3}+672x^{3}+896x$$

Combine 4x^{2} and 1216x^{2} to get 1220x^{2}.

$$1220x^{2}-12x+9+16x^{2}\left(-x\right)^{3}-96x^{4}+192x^{2}\left(-x\right)-112x\left(-x\right)^{3}+672x^{3}+896x$$

Combine -12x and 896x to get 884x.

$$1220x^{2}+884x+9+16x^{2}\left(-x\right)^{3}-96x^{4}+192x^{2}\left(-x\right)-112x\left(-x\right)^{3}+672x^{3}$$

Expand \left(-x\right)^{3}.

$$1220x^{2}+884x+9+16x^{2}\left(-1\right)^{3}x^{3}-96x^{4}+192x^{2}\left(-1\right)x-112x\left(-x\right)^{3}+672x^{3}$$

Calculate -1 to the power of 3 and get -1.

$$1220x^{2}+884x+9+16x^{2}\left(-1\right)x^{3}-96x^{4}+192x^{2}\left(-1\right)x-112x\left(-x\right)^{3}+672x^{3}$$

Multiply 16 and -1 to get -16.

$$1220x^{2}+884x+9-16x^{2}x^{3}-96x^{4}+192x^{2}\left(-1\right)x-112x\left(-x\right)^{3}+672x^{3}$$

To multiply powers of the same base, add their exponents. Add 2 and 3 to get 5.

$$1220x^{2}+884x+9-16x^{5}-96x^{4}+192x^{2}\left(-1\right)x-112x\left(-x\right)^{3}+672x^{3}$$

To multiply powers of the same base, add their exponents. Add 2 and 1 to get 3.

$$1220x^{2}+884x+9-16x^{5}-96x^{4}+192x^{3}\left(-1\right)-112x\left(-x\right)^{3}+672x^{3}$$

Multiply 192 and -1 to get -192.

$$1220x^{2}+884x+9-16x^{5}-96x^{4}-192x^{3}-112x\left(-x\right)^{3}+672x^{3}$$

Expand \left(-x\right)^{3}.

$$1220x^{2}+884x+9-16x^{5}-96x^{4}-192x^{3}-112x\left(-1\right)^{3}x^{3}+672x^{3}$$

Calculate -1 to the power of 3 and get -1.

$$1220x^{2}+884x+9-16x^{5}-96x^{4}-192x^{3}-112x\left(-1\right)x^{3}+672x^{3}$$

Multiply -112 and -1 to get 112.

$$1220x^{2}+884x+9-16x^{5}-96x^{4}-192x^{3}+112xx^{3}+672x^{3}$$

To multiply powers of the same base, add their exponents. Add 1 and 3 to get 4.

$$1220x^{2}+884x+9-16x^{5}-96x^{4}-192x^{3}+112x^{4}+672x^{3}$$

Combine -96x^{4} and 112x^{4} to get 16x^{4}.

$$1220x^{2}+884x+9-16x^{5}+16x^{4}-192x^{3}+672x^{3}$$

Combine -192x^{3} and 672x^{3} to get 480x^{3}.

$$1220x^{2}+884x+9-16x^{5}+16x^{4}+480x^{3}$$

Expand

$$9+884x+1220x^{2}+480x^{3}+16x^{4}-16x^{5}$$

Solution Steps

Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(2x-3\right)^{2}.

$$4x^{2}-12x+9+4x\left(x-7\right)\times 4\left(-x-2\right)^{3}$$

Multiply 4 and 4 to get 16.

$$4x^{2}-12x+9+16x\left(x-7\right)\left(-x-2\right)^{3}$$

Use binomial theorem \left(a-b\right)^{3}=a^{3}-3a^{2}b+3ab^{2}-b^{3} to expand \left(-x-2\right)^{3}.

$$4x^{2}-12x+9+16x\left(x-7\right)\left(\left(-x\right)^{3}-6\left(-x\right)^{2}+12\left(-x\right)-8\right)$$

Calculate -x to the power of 2 and get x^{2}.

$$4x^{2}-12x+9+16x\left(x-7\right)\left(\left(-x\right)^{3}-6x^{2}+12\left(-x\right)-8\right)$$

Use the distributive property to multiply 16x by x-7.

$$4x^{2}-12x+9+\left(16x^{2}-112x\right)\left(\left(-x\right)^{3}-6x^{2}+12\left(-x\right)-8\right)$$

Use the distributive property to multiply 16x^{2}-112x by \left(-x\right)^{3}-6x^{2}+12\left(-x\right)-8.

$$4x^{2}-12x+9+16x^{2}\left(-x\right)^{3}-96x^{4}+192x^{2}\left(-x\right)-128x^{2}-112x\left(-x\right)^{3}+672x^{3}-1344x\left(-x\right)+896x$$

Multiply -1344 and -1 to get 1344.

$$4x^{2}-12x+9+16x^{2}\left(-x\right)^{3}-96x^{4}+192x^{2}\left(-x\right)-128x^{2}-112x\left(-x\right)^{3}+672x^{3}+1344xx+896x$$

Multiply x and x to get x^{2}.

$$4x^{2}-12x+9+16x^{2}\left(-x\right)^{3}-96x^{4}+192x^{2}\left(-x\right)-128x^{2}-112x\left(-x\right)^{3}+672x^{3}+1344x^{2}+896x$$

Combine -128x^{2} and 1344x^{2} to get 1216x^{2}.

$$4x^{2}-12x+9+16x^{2}\left(-x\right)^{3}-96x^{4}+192x^{2}\left(-x\right)+1216x^{2}-112x\left(-x\right)^{3}+672x^{3}+896x$$

Combine 4x^{2} and 1216x^{2} to get 1220x^{2}.

$$1220x^{2}-12x+9+16x^{2}\left(-x\right)^{3}-96x^{4}+192x^{2}\left(-x\right)-112x\left(-x\right)^{3}+672x^{3}+896x$$

Combine -12x and 896x to get 884x.

$$1220x^{2}+884x+9+16x^{2}\left(-x\right)^{3}-96x^{4}+192x^{2}\left(-x\right)-112x\left(-x\right)^{3}+672x^{3}$$

Expand \left(-x\right)^{3}.

$$1220x^{2}+884x+9+16x^{2}\left(-1\right)^{3}x^{3}-96x^{4}+192x^{2}\left(-1\right)x-112x\left(-x\right)^{3}+672x^{3}$$

Calculate -1 to the power of 3 and get -1.

$$1220x^{2}+884x+9+16x^{2}\left(-1\right)x^{3}-96x^{4}+192x^{2}\left(-1\right)x-112x\left(-x\right)^{3}+672x^{3}$$

Multiply 16 and -1 to get -16.

$$1220x^{2}+884x+9-16x^{2}x^{3}-96x^{4}+192x^{2}\left(-1\right)x-112x\left(-x\right)^{3}+672x^{3}$$

To multiply powers of the same base, add their exponents. Add 2 and 3 to get 5.

$$1220x^{2}+884x+9-16x^{5}-96x^{4}+192x^{2}\left(-1\right)x-112x\left(-x\right)^{3}+672x^{3}$$

To multiply powers of the same base, add their exponents. Add 2 and 1 to get 3.

$$1220x^{2}+884x+9-16x^{5}-96x^{4}+192x^{3}\left(-1\right)-112x\left(-x\right)^{3}+672x^{3}$$

Multiply 192 and -1 to get -192.

$$1220x^{2}+884x+9-16x^{5}-96x^{4}-192x^{3}-112x\left(-x\right)^{3}+672x^{3}$$

Expand \left(-x\right)^{3}.

$$1220x^{2}+884x+9-16x^{5}-96x^{4}-192x^{3}-112x\left(-1\right)^{3}x^{3}+672x^{3}$$

Calculate -1 to the power of 3 and get -1.

$$1220x^{2}+884x+9-16x^{5}-96x^{4}-192x^{3}-112x\left(-1\right)x^{3}+672x^{3}$$

Multiply -112 and -1 to get 112.

$$1220x^{2}+884x+9-16x^{5}-96x^{4}-192x^{3}+112xx^{3}+672x^{3}$$

To multiply powers of the same base, add their exponents. Add 1 and 3 to get 4.

$$1220x^{2}+884x+9-16x^{5}-96x^{4}-192x^{3}+112x^{4}+672x^{3}$$

Combine -96x^{4} and 112x^{4} to get 16x^{4}.

$$1220x^{2}+884x+9-16x^{5}+16x^{4}-192x^{3}+672x^{3}$$

Combine -192x^{3} and 672x^{3} to get 480x^{3}.

$$1220x^{2}+884x+9-16x^{5}+16x^{4}+480x^{3}$$