Solve (2x-3):4+x*2geq1

$$( 2 x - 3 ) : 4 + x \cdot 2 \geq 1$$

Solve for x

$$x\geq \frac{7}{10}$$

Solution Steps

Multiply both sides of the equation by 4. Since 4 is positive, the inequality direction remains the same.

$$2x-3+4x\times 2\geq 4$$

Multiply 4 and 2 to get 8.

$$2x-3+8x\geq 4$$

Combine 2x and 8x to get 10x.

$$10x-3\geq 4$$

Add 3 to both sides.

$$10x\geq 4+3$$

Add 4 and 3 to get 7.

$$10x\geq 7$$

Divide both sides by 10. Since 10 is positive, the inequality direction remains the same.

$$x\geq \frac{7}{10}$$