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4x^{2}-4x+1-9=16
Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(2x-1\right)^{2}.
4x^{2}-4x-8=16
Subtract 9 from 1 to get -8.
4x^{2}-4x-8-16=0
Subtract 16 from both sides.
4x^{2}-4x-24=0
Subtract 16 from -8 to get -24.
x^{2}-x-6=0
Divide both sides by 4.
a+b=-1 ab=1\left(-6\right)=-6
To solve the equation, factor the left hand side by grouping. First, left hand side needs to be rewritten as x^{2}+ax+bx-6. To find a and b, set up a system to be solved.
1,-6 2,-3
Since ab is negative, a and b have the opposite signs. Since a+b is negative, the negative number has greater absolute value than the positive. List all such integer pairs that give product -6.
1-6=-5 2-3=-1
Calculate the sum for each pair.
a=-3 b=2
The solution is the pair that gives sum -1.
\left(x^{2}-3x\right)+\left(2x-6\right)
Rewrite x^{2}-x-6 as \left(x^{2}-3x\right)+\left(2x-6\right).
x\left(x-3\right)+2\left(x-3\right)
Factor out x in the first and 2 in the second group.
\left(x-3\right)\left(x+2\right)
Factor out common term x-3 by using distributive property.
x=3 x=-2
To find equation solutions, solve x-3=0 and x+2=0.
4x^{2}-4x+1-9=16
Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(2x-1\right)^{2}.
4x^{2}-4x-8=16
Subtract 9 from 1 to get -8.
4x^{2}-4x-8-16=0
Subtract 16 from both sides.
4x^{2}-4x-24=0
Subtract 16 from -8 to get -24.
x=\frac{-\left(-4\right)±\sqrt{\left(-4\right)^{2}-4\times 4\left(-24\right)}}{2\times 4}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 4 for a, -4 for b, and -24 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{-\left(-4\right)±\sqrt{16-4\times 4\left(-24\right)}}{2\times 4}
Square -4.
x=\frac{-\left(-4\right)±\sqrt{16-16\left(-24\right)}}{2\times 4}
Multiply -4 times 4.
x=\frac{-\left(-4\right)±\sqrt{16+384}}{2\times 4}
Multiply -16 times -24.
x=\frac{-\left(-4\right)±\sqrt{400}}{2\times 4}
Add 16 to 384.
x=\frac{-\left(-4\right)±20}{2\times 4}
Take the square root of 400.
x=\frac{4±20}{2\times 4}
The opposite of -4 is 4.
x=\frac{4±20}{8}
Multiply 2 times 4.
x=\frac{24}{8}
Now solve the equation x=\frac{4±20}{8} when ± is plus. Add 4 to 20.
x=3
Divide 24 by 8.
x=-\frac{16}{8}
Now solve the equation x=\frac{4±20}{8} when ± is minus. Subtract 20 from 4.
x=-2
Divide -16 by 8.
x=3 x=-2
The equation is now solved.
4x^{2}-4x+1-9=16
Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(2x-1\right)^{2}.
4x^{2}-4x-8=16
Subtract 9 from 1 to get -8.
4x^{2}-4x=16+8
Add 8 to both sides.
4x^{2}-4x=24
Add 16 and 8 to get 24.
\frac{4x^{2}-4x}{4}=\frac{24}{4}
Divide both sides by 4.
x^{2}+\left(-\frac{4}{4}\right)x=\frac{24}{4}
Dividing by 4 undoes the multiplication by 4.
x^{2}-x=\frac{24}{4}
Divide -4 by 4.
x^{2}-x=6
Divide 24 by 4.
x^{2}-x+\left(-\frac{1}{2}\right)^{2}=6+\left(-\frac{1}{2}\right)^{2}
Divide -1, the coefficient of the x term, by 2 to get -\frac{1}{2}. Then add the square of -\frac{1}{2} to both sides of the equation. This step makes the left hand side of the equation a perfect square.
x^{2}-x+\frac{1}{4}=6+\frac{1}{4}
Square -\frac{1}{2} by squaring both the numerator and the denominator of the fraction.
x^{2}-x+\frac{1}{4}=\frac{25}{4}
Add 6 to \frac{1}{4}.
\left(x-\frac{1}{2}\right)^{2}=\frac{25}{4}
Factor x^{2}-x+\frac{1}{4}. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(x-\frac{1}{2}\right)^{2}}=\sqrt{\frac{25}{4}}
Take the square root of both sides of the equation.
x-\frac{1}{2}=\frac{5}{2} x-\frac{1}{2}=-\frac{5}{2}
Simplify.
x=3 x=-2
Add \frac{1}{2} to both sides of the equation.