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4x^{2}-4x+1-3x-23=4x^{2}-2x+\frac{1}{3}x
Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(2x-1\right)^{2}.
4x^{2}-7x+1-23=4x^{2}-2x+\frac{1}{3}x
Combine -4x and -3x to get -7x.
4x^{2}-7x-22=4x^{2}-2x+\frac{1}{3}x
Subtract 23 from 1 to get -22.
4x^{2}-7x-22=4x^{2}-\frac{5}{3}x
Combine -2x and \frac{1}{3}x to get -\frac{5}{3}x.
4x^{2}-7x-22-4x^{2}=-\frac{5}{3}x
Subtract 4x^{2} from both sides.
-7x-22=-\frac{5}{3}x
Combine 4x^{2} and -4x^{2} to get 0.
-7x-22+\frac{5}{3}x=0
Add \frac{5}{3}x to both sides.
-\frac{16}{3}x-22=0
Combine -7x and \frac{5}{3}x to get -\frac{16}{3}x.
-\frac{16}{3}x=22
Add 22 to both sides. Anything plus zero gives itself.
x=22\left(-\frac{3}{16}\right)
Multiply both sides by -\frac{3}{16}, the reciprocal of -\frac{16}{3}.
x=-\frac{33}{8}
Multiply 22 and -\frac{3}{16} to get -\frac{33}{8}.