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Solve for x (complex solution)
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4x^{2}-4x+1=4x^{2}-4x+1
Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(2x-1\right)^{2}.
4x^{2}-4x+1-4x^{2}=-4x+1
Subtract 4x^{2} from both sides.
-4x+1=-4x+1
Combine 4x^{2} and -4x^{2} to get 0.
-4x+1+4x=1
Add 4x to both sides.
1=1
Combine -4x and 4x to get 0.
\text{true}
Compare 1 and 1.
x\in \mathrm{C}
This is true for any x.
4x^{2}-4x+1=4x^{2}-4x+1
Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(2x-1\right)^{2}.
4x^{2}-4x+1-4x^{2}=-4x+1
Subtract 4x^{2} from both sides.
-4x+1=-4x+1
Combine 4x^{2} and -4x^{2} to get 0.
-4x+1+4x=1
Add 4x to both sides.
1=1
Combine -4x and 4x to get 0.
\text{true}
Compare 1 and 1.
x\in \mathrm{R}
This is true for any x.