Evaluate
\frac{\left(6x-1\right)^{3}}{27}
Expand
8x^{3}-4x^{2}+\frac{2x}{3}-\frac{1}{27}
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8x^{3}-4x^{2}+\frac{2}{3}x-\frac{1}{27}
Use binomial theorem \left(a-b\right)^{3}=a^{3}-3a^{2}b+3ab^{2}-b^{3} to expand \left(2x-\frac{1}{3}\right)^{3}.
8x^{3}-4x^{2}+\frac{2}{3}x-\frac{1}{27}
Use binomial theorem \left(a-b\right)^{3}=a^{3}-3a^{2}b+3ab^{2}-b^{3} to expand \left(2x-\frac{1}{3}\right)^{3}.
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