Solve (2x^-3y)^-1

$$( 2 x ^ { - 3 } y ) ^ { - 1 }$$

Evaluate

$$\frac{x^{3}}{2y}$$

Solution Steps

Use the rules of exponents to simplify the expression.

$$\frac{1}{2x^{-3}y^{1}}$$

To raise the product of two or more numbers to a power, raise each number to the power and take their product.

$$\frac{1}{2}\times \frac{1}{x^{-3}}\times \frac{1}{y^{1}}$$

To raise a power to another power, multiply the exponents.

$$\frac{1}{2}x^{-3\left(-1\right)}\times \frac{1}{y}$$

Multiply -3 times -1.

$$\frac{1}{2}x^{3}\times \frac{1}{y}$$

Differentiate w.r.t. x

$$\frac{3x^{2}}{2y}$$