( 2 x + 5 y + z = 3
Solve for x
x=\frac{3-z-5y}{2}
Solve for y
y=\frac{3-z-2x}{5}
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2x+z=3-5y
Subtract 5y from both sides.
2x=3-5y-z
Subtract z from both sides.
2x=3-z-5y
The equation is in standard form.
\frac{2x}{2}=\frac{3-z-5y}{2}
Divide both sides by 2.
x=\frac{3-z-5y}{2}
Dividing by 2 undoes the multiplication by 2.
5y+z=3-2x
Subtract 2x from both sides.
5y=3-2x-z
Subtract z from both sides.
5y=3-z-2x
The equation is in standard form.
\frac{5y}{5}=\frac{3-z-2x}{5}
Divide both sides by 5.
y=\frac{3-z-2x}{5}
Dividing by 5 undoes the multiplication by 5.
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