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2x+5\leq 0 4-3x\leq 0
For the product to be ≥0, 2x+5 and 4-3x have to be both ≤0 or both ≥0. Consider the case when 2x+5 and 4-3x are both ≤0.
x\in \emptyset
This is false for any x.
4-3x\geq 0 2x+5\geq 0
Consider the case when 2x+5 and 4-3x are both ≥0.
x\in \begin{bmatrix}-\frac{5}{2},\frac{4}{3}\end{bmatrix}
The solution satisfying both inequalities is x\in \left[-\frac{5}{2},\frac{4}{3}\right].
x\in \begin{bmatrix}-\frac{5}{2},\frac{4}{3}\end{bmatrix}
The final solution is the union of the obtained solutions.