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4x^{2}+12x\sqrt{3}+9\left(\sqrt{3}\right)^{2}
Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(2x+3\sqrt{3}\right)^{2}.
4x^{2}+12x\sqrt{3}+9\times 3
The square of \sqrt{3} is 3.
4x^{2}+12x\sqrt{3}+27
Multiply 9 and 3 to get 27.
4x^{2}+12x\sqrt{3}+9\left(\sqrt{3}\right)^{2}
Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(2x+3\sqrt{3}\right)^{2}.
4x^{2}+12x\sqrt{3}+9\times 3
The square of \sqrt{3} is 3.
4x^{2}+12x\sqrt{3}+27
Multiply 9 and 3 to get 27.