Solve (2x+1)(4x^2-2x+1)-2x(4x^2+1)=0

$$( 2 x + 1 ) ( 4 x ^ { 2 } - 2 x + 1 ) - 2 x ( 4 x ^ { 2 } + 1 ) = 0$$

Solve for x

$$x=\frac{1}{2}=0.5$$

Steps for Solving Linear Equation

Use the distributive property to multiply 2x+1 by 4x^{2}-2x+1 and combine like terms.

$$8x^{3}+1-2x\left(4x^{2}+1\right)=0$$

Use the distributive property to multiply -2x by 4x^{2}+1.

$$8x^{3}+1-8x^{3}-2x=0$$

Combine 8x^{3} and -8x^{3} to get 0.

$$1-2x=0$$

Subtract 1 from both sides. Anything subtracted from zero gives its negation.

$$-2x=-1$$

Divide both sides by -2.

$$x=\frac{-1}{-2}$$

Fraction \frac{-1}{-2} can be simplified to \frac{1}{2} by removing the negative sign from both the numerator and the denominator.

$$x=\frac{1}{2}$$