Solve for x
x=\frac{\sqrt{15}}{8}+\frac{31}{64}\approx 0.968497918
x=-\frac{\sqrt{15}}{8}+\frac{31}{64}\approx 0.000252082
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4x^{2}+\frac{1}{8}x+\frac{1}{1024}=4x
Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(2x+\frac{1}{32}\right)^{2}.
4x^{2}+\frac{1}{8}x+\frac{1}{1024}-4x=0
Subtract 4x from both sides.
4x^{2}-\frac{31}{8}x+\frac{1}{1024}=0
Combine \frac{1}{8}x and -4x to get -\frac{31}{8}x.
x=\frac{-\left(-\frac{31}{8}\right)±\sqrt{\left(-\frac{31}{8}\right)^{2}-4\times 4\times \frac{1}{1024}}}{2\times 4}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 4 for a, -\frac{31}{8} for b, and \frac{1}{1024} for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{-\left(-\frac{31}{8}\right)±\sqrt{\frac{961}{64}-4\times 4\times \frac{1}{1024}}}{2\times 4}
Square -\frac{31}{8} by squaring both the numerator and the denominator of the fraction.
x=\frac{-\left(-\frac{31}{8}\right)±\sqrt{\frac{961}{64}-16\times \frac{1}{1024}}}{2\times 4}
Multiply -4 times 4.
x=\frac{-\left(-\frac{31}{8}\right)±\sqrt{\frac{961-1}{64}}}{2\times 4}
Multiply -16 times \frac{1}{1024}.
x=\frac{-\left(-\frac{31}{8}\right)±\sqrt{15}}{2\times 4}
Add \frac{961}{64} to -\frac{1}{64} by finding a common denominator and adding the numerators. Then reduce the fraction to lowest terms if possible.
x=\frac{\frac{31}{8}±\sqrt{15}}{2\times 4}
The opposite of -\frac{31}{8} is \frac{31}{8}.
x=\frac{\frac{31}{8}±\sqrt{15}}{8}
Multiply 2 times 4.
x=\frac{\sqrt{15}+\frac{31}{8}}{8}
Now solve the equation x=\frac{\frac{31}{8}±\sqrt{15}}{8} when ± is plus. Add \frac{31}{8} to \sqrt{15}.
x=\frac{\sqrt{15}}{8}+\frac{31}{64}
Divide \frac{31}{8}+\sqrt{15} by 8.
x=\frac{\frac{31}{8}-\sqrt{15}}{8}
Now solve the equation x=\frac{\frac{31}{8}±\sqrt{15}}{8} when ± is minus. Subtract \sqrt{15} from \frac{31}{8}.
x=-\frac{\sqrt{15}}{8}+\frac{31}{64}
Divide \frac{31}{8}-\sqrt{15} by 8.
x=\frac{\sqrt{15}}{8}+\frac{31}{64} x=-\frac{\sqrt{15}}{8}+\frac{31}{64}
The equation is now solved.
4x^{2}+\frac{1}{8}x+\frac{1}{1024}=4x
Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(2x+\frac{1}{32}\right)^{2}.
4x^{2}+\frac{1}{8}x+\frac{1}{1024}-4x=0
Subtract 4x from both sides.
4x^{2}-\frac{31}{8}x+\frac{1}{1024}=0
Combine \frac{1}{8}x and -4x to get -\frac{31}{8}x.
4x^{2}-\frac{31}{8}x=-\frac{1}{1024}
Subtract \frac{1}{1024} from both sides. Anything subtracted from zero gives its negation.
\frac{4x^{2}-\frac{31}{8}x}{4}=-\frac{\frac{1}{1024}}{4}
Divide both sides by 4.
x^{2}+\left(-\frac{\frac{31}{8}}{4}\right)x=-\frac{\frac{1}{1024}}{4}
Dividing by 4 undoes the multiplication by 4.
x^{2}-\frac{31}{32}x=-\frac{\frac{1}{1024}}{4}
Divide -\frac{31}{8} by 4.
x^{2}-\frac{31}{32}x=-\frac{1}{4096}
Divide -\frac{1}{1024} by 4.
x^{2}-\frac{31}{32}x+\left(-\frac{31}{64}\right)^{2}=-\frac{1}{4096}+\left(-\frac{31}{64}\right)^{2}
Divide -\frac{31}{32}, the coefficient of the x term, by 2 to get -\frac{31}{64}. Then add the square of -\frac{31}{64} to both sides of the equation. This step makes the left hand side of the equation a perfect square.
x^{2}-\frac{31}{32}x+\frac{961}{4096}=\frac{-1+961}{4096}
Square -\frac{31}{64} by squaring both the numerator and the denominator of the fraction.
x^{2}-\frac{31}{32}x+\frac{961}{4096}=\frac{15}{64}
Add -\frac{1}{4096} to \frac{961}{4096} by finding a common denominator and adding the numerators. Then reduce the fraction to lowest terms if possible.
\left(x-\frac{31}{64}\right)^{2}=\frac{15}{64}
Factor x^{2}-\frac{31}{32}x+\frac{961}{4096}. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(x-\frac{31}{64}\right)^{2}}=\sqrt{\frac{15}{64}}
Take the square root of both sides of the equation.
x-\frac{31}{64}=\frac{\sqrt{15}}{8} x-\frac{31}{64}=-\frac{\sqrt{15}}{8}
Simplify.
x=\frac{\sqrt{15}}{8}+\frac{31}{64} x=-\frac{\sqrt{15}}{8}+\frac{31}{64}
Add \frac{31}{64} to both sides of the equation.
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