Solve (2isqrt{2})^2

$$( 2 i \sqrt { 2 } ) ^ { 2 }$$

Evaluate

$$-8$$

Solution Steps

Expand \left(2i\sqrt{2}\right)^{2}.

$$\left(2i\right)^{2}\left(\sqrt{2}\right)^{2}$$

Calculate 2i to the power of 2 and get -4.

$$-4\left(\sqrt{2}\right)^{2}$$

The square of \sqrt{2} is 2.

$$-4\times 2$$

Multiply -4 and 2 to get -8.

$$-8$$

Real Part

$$-8$$

Solution Steps

Expand \left(2i\sqrt{2}\right)^{2}.

$$Re(\left(2i\right)^{2}\left(\sqrt{2}\right)^{2})$$

Calculate 2i to the power of 2 and get -4.

$$Re(-4\left(\sqrt{2}\right)^{2})$$

The square of \sqrt{2} is 2.

$$Re(-4\times 2)$$

Multiply -4 and 2 to get -8.

$$Re(-8)$$

The real part of -8 is -8.

$$-8$$