Solve (2c+2)*(2c-5)=(c+1)*(4c-3)

$$( 2 c + 2 ) \cdot ( 2 c - 5 ) = ( c + 1 ) \cdot ( 4 c - 3 )$$

Solve for c

$$c=-1$$

Steps for Solving Linear Equation

Use the distributive property to multiply 2c+2 by 2c-5 and combine like terms.

$$4c^{2}-6c-10=\left(c+1\right)\left(4c-3\right)$$

Use the distributive property to multiply c+1 by 4c-3 and combine like terms.

$$4c^{2}-6c-10=4c^{2}+c-3$$

Subtract 4c^{2} from both sides.

$$4c^{2}-6c-10-4c^{2}=c-3$$

Combine 4c^{2} and -4c^{2} to get 0.

$$-6c-10=c-3$$

Subtract c from both sides.

$$-6c-10-c=-3$$

Combine -6c and -c to get -7c.

$$-7c-10=-3$$

Add 10 to both sides.

$$-7c=-3+10$$

Add -3 and 10 to get 7.

$$-7c=7$$

Divide both sides by -7.

$$c=\frac{7}{-7}$$

Divide 7 by -7 to get -1.

$$c=-1$$