Solve (2ab^2c^3)*(-3a^2bc)*(-bc)

$$( 2 a b ^ { 2 } c ^ { 3 } ) \cdot ( - 3 a ^ { 2 } b c ) \cdot ( - b c )$$

Evaluate

$$6a^{3}b^{4}c^{5}$$

Solution Steps

To multiply powers of the same base, add their exponents. Add 1 and 2 to get 3.

$$2a^{3}b^{2}c^{3}\left(-3\right)bc\left(-b\right)c$$

To multiply powers of the same base, add their exponents. Add 2 and 1 to get 3.

$$2a^{3}b^{3}c^{3}\left(-3\right)c\left(-b\right)c$$

To multiply powers of the same base, add their exponents. Add 3 and 1 to get 4.

$$2a^{3}b^{3}c^{4}\left(-3\right)\left(-b\right)c$$

To multiply powers of the same base, add their exponents. Add 4 and 1 to get 5.

$$2a^{3}b^{3}c^{5}\left(-3\right)\left(-b\right)$$

Multiply 2 and -3 to get -6.

$$-6a^{3}b^{3}c^{5}\left(-b\right)$$

Multiply -6 and -1 to get 6.

$$6a^{3}b^{3}c^{5}b$$

To multiply powers of the same base, add their exponents. Add 3 and 1 to get 4.

$$6a^{3}b^{4}c^{5}$$

Differentiate w.r.t. a

$$18a^{2}b^{4}c^{5}$$