Solve (2a5+{3*02*(6*125div96-2746)}

$$( 2 a 5 + \{ 3 \cdot 02 \times ( 6 \cdot 125 \div 96 - 2746 ) \}$$

Evaluate

$$2a_{5}-\frac{131433}{8}$$

Solution Steps

Multiply 3 and 2 to get 6.

$$2a_{5}+6\left(\frac{6\times 125}{96}-2746\right)$$

Multiply 6 and 125 to get 750.

$$2a_{5}+6\left(\frac{750}{96}-2746\right)$$

Reduce the fraction \frac{750}{96} to lowest terms by extracting and canceling out 6.

$$2a_{5}+6\left(\frac{125}{16}-2746\right)$$

Convert 2746 to fraction \frac{43936}{16}.

$$2a_{5}+6\left(\frac{125}{16}-\frac{43936}{16}\right)$$

Since \frac{125}{16} and \frac{43936}{16} have the same denominator, subtract them by subtracting their numerators.

$$2a_{5}+6\times \frac{125-43936}{16}$$

Subtract 43936 from 125 to get -43811.

$$2a_{5}+6\left(-\frac{43811}{16}\right)$$

Express 6\left(-\frac{43811}{16}\right) as a single fraction.

$$2a_{5}+\frac{6\left(-43811\right)}{16}$$

Multiply 6 and -43811 to get -262866.

$$2a_{5}+\frac{-262866}{16}$$

Reduce the fraction \frac{-262866}{16} to lowest terms by extracting and canceling out 2.

$$2a_{5}+-\frac{131433}{8}$$

Differentiate w.r.t. a_5

$$2$$