Solve (2a+8)x+3b-4=(b-1))

$$( 2 a + 8 ) x + 3 b - 4 = ( b - 1 ) )$$

Solve for a (complex solution)

$$\left\{\begin{matrix}a=\frac{3-2b-8x}{2x}\text{, }&x\neq 0\\a\in \mathrm{C}\text{, }&b=\frac{3}{2}\text{ and }x=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Use the distributive property to multiply 2a+8 by x.

$$2ax+8x+3b-4=b-1$$

Subtract 8x from both sides.

$$2ax+3b-4=b-1-8x$$

Subtract 3b from both sides.

$$2ax-4=b-1-8x-3b$$

Combine b and -3b to get -2b.

$$2ax-4=-2b-1-8x$$

Add 4 to both sides.

$$2ax=-2b-1-8x+4$$

Add -1 and 4 to get 3.

$$2ax=-2b+3-8x$$

The equation is in standard form.

$$2xa=3-2b-8x$$

Divide both sides by 2x.

$$\frac{2xa}{2x}=\frac{3-2b-8x}{2x}$$

Dividing by 2x undoes the multiplication by 2x.

$$a=\frac{3-2b-8x}{2x}$$

Divide -2b+3-8x by 2x.

$$a=\frac{\frac{3}{2}-b}{x}-4$$

Solve for a

$$\left\{\begin{matrix}a=\frac{3-2b-8x}{2x}\text{, }&x\neq 0\\a\in \mathrm{R}\text{, }&b=\frac{3}{2}\text{ and }x=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Use the distributive property to multiply 2a+8 by x.

$$2ax+8x+3b-4=b-1$$

Subtract 8x from both sides.

$$2ax+3b-4=b-1-8x$$

Subtract 3b from both sides.

$$2ax-4=b-1-8x-3b$$

Combine b and -3b to get -2b.

$$2ax-4=-2b-1-8x$$

Add 4 to both sides.

$$2ax=-2b-1-8x+4$$

Add -1 and 4 to get 3.

$$2ax=-2b+3-8x$$

The equation is in standard form.

$$2xa=3-2b-8x$$

Divide both sides by 2x.

$$\frac{2xa}{2x}=\frac{3-2b-8x}{2x}$$

Dividing by 2x undoes the multiplication by 2x.

$$a=\frac{3-2b-8x}{2x}$$

Divide -2b+3-8x by 2x.

$$a=\frac{\frac{3}{2}-b}{x}-4$$

Solve for b

$$b=\frac{3}{2}-4x-ax$$

Steps for Solving Linear Equation

Use the distributive property to multiply 2a+8 by x.

$$2ax+8x+3b-4=b-1$$

Subtract b from both sides.

$$2ax+8x+3b-4-b=-1$$

Combine 3b and -b to get 2b.

$$2ax+8x+2b-4=-1$$

Subtract 2ax from both sides.

$$8x+2b-4=-1-2ax$$

Subtract 8x from both sides.

$$2b-4=-1-2ax-8x$$

Add 4 to both sides.

$$2b=-1-2ax-8x+4$$

Add -1 and 4 to get 3.

$$2b=3-2ax-8x$$

The equation is in standard form.

$$2b=3-8x-2ax$$

Divide both sides by 2.

$$\frac{2b}{2}=\frac{3-8x-2ax}{2}$$

Dividing by 2 undoes the multiplication by 2.

$$b=\frac{3-8x-2ax}{2}$$

Divide 3-2ax-8x by 2.

$$b=\frac{3}{2}-4x-ax$$