Solve for x
x\geq -2
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4-x^{2}\geq -x^{2}-2x
Consider \left(2-x\right)\left(2+x\right). Multiplication can be transformed into difference of squares using the rule: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}. Square 2.
4-x^{2}+x^{2}\geq -2x
Add x^{2} to both sides.
4\geq -2x
Combine -x^{2} and x^{2} to get 0.
-2x\leq 4
Swap sides so that all variable terms are on the left hand side. This changes the sign direction.
x\geq \frac{4}{-2}
Divide both sides by -2. Since -2 is negative, the inequality direction is changed.
x\geq -2
Divide 4 by -2 to get -2.
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