Solve (2-h)^2+(-2-k)^2=r^2

$$( 2 - h ) ^ { 2 } + ( - 2 - k ) ^ { 2 } = r ^ { 2 }$$

Solve for h (complex solution)

$$h=\sqrt{-\left(k+2\right)^{2}+r^{2}}+2$$

$$h=-\sqrt{-\left(k+2\right)^{2}+r^{2}}+2$$

Solve for k (complex solution)

$$k=\sqrt{-\left(h-2\right)^{2}+r^{2}}-2$$

$$k=-\sqrt{-\left(h-2\right)^{2}+r^{2}}-2$$

Solve for h

$$h=\sqrt{-\left(k+2\right)^{2}+r^{2}}+2$$

$$h=-\sqrt{-\left(k+2\right)^{2}+r^{2}}+2\text{, }k\geq -|r|-2\text{ and }k\leq |r|-2$$

Solve for k

$$k=\sqrt{r^{2}-h^{2}+4h-4}-2$$

$$k=-\sqrt{r^{2}-h^{2}+4h-4}-2\text{, }h\geq -|r|+2\text{ and }h\leq |r|+2$$