Solve (2-a)(3a+2)(1-a)

$$( 2 - a ) ( 3 a + 2 ) ( 1 - a )$$

Evaluate

$$\left(a-2\right)\left(a-1\right)\left(3a+2\right)$$

Solution Steps

Apply the distributive property by multiplying each term of 2-a by each term of 3a+2.

$$\left(6a+4-3a^{2}-2a\right)\left(1-a\right)$$

Combine 6a and -2a to get 4a.

$$\left(4a+4-3a^{2}\right)\left(1-a\right)$$

Apply the distributive property by multiplying each term of 4a+4-3a^{2} by each term of 1-a.

$$4a-4a^{2}+4-4a-3a^{2}+3a^{3}$$

Combine 4a and -4a to get 0.

$$-4a^{2}+4-3a^{2}+3a^{3}$$

Combine -4a^{2} and -3a^{2} to get -7a^{2}.

$$-7a^{2}+4+3a^{3}$$

Expand

$$3a^{3}-7a^{2}+4$$

Solution Steps

Apply the distributive property by multiplying each term of 2-a by each term of 3a+2.

$$\left(6a+4-3a^{2}-2a\right)\left(1-a\right)$$

Combine 6a and -2a to get 4a.

$$\left(4a+4-3a^{2}\right)\left(1-a\right)$$

Apply the distributive property by multiplying each term of 4a+4-3a^{2} by each term of 1-a.

$$4a-4a^{2}+4-4a-3a^{2}+3a^{3}$$

Combine 4a and -4a to get 0.

$$-4a^{2}+4-3a^{2}+3a^{3}$$

Combine -4a^{2} and -3a^{2} to get -7a^{2}.

$$-7a^{2}+4+3a^{3}$$