Solve (2-3(7/4))^2-(3(1/4)-1)(3(9/4)+7)=2

$$( 2 - 3 ( \frac { 7 } { 4 } ) ) ^ { 2 } - ( 3 ( \frac { 1 } { 4 } ) - 1 ) ( 3 ( \frac { 9 } { 4 } ) + 7 ) = 2$$

Verify

Solution Steps

Multiply 3 and \frac{7}{4} to get \frac{21}{4}.

$$\left(2-\frac{21}{4}\right)^{2}-\left(3\times \frac{1}{4}-1\right)\left(3\times \frac{9}{4}+7\right)=2$$

Subtract \frac{21}{4} from 2 to get -\frac{13}{4}.

$$\left(-\frac{13}{4}\right)^{2}-\left(3\times \frac{1}{4}-1\right)\left(3\times \frac{9}{4}+7\right)=2$$

Calculate -\frac{13}{4} to the power of 2 and get \frac{169}{16}.

$$\frac{169}{16}-\left(3\times \frac{1}{4}-1\right)\left(3\times \frac{9}{4}+7\right)=2$$

Multiply 3 and \frac{1}{4} to get \frac{3}{4}.

$$\frac{169}{16}-\left(\frac{3}{4}-1\right)\left(3\times \frac{9}{4}+7\right)=2$$

Subtract 1 from \frac{3}{4} to get -\frac{1}{4}.

$$\frac{169}{16}-\left(-\frac{1}{4}\left(3\times \frac{9}{4}+7\right)\right)=2$$

Multiply 3 and \frac{9}{4} to get \frac{27}{4}.

$$\frac{169}{16}-\left(-\frac{1}{4}\left(\frac{27}{4}+7\right)\right)=2$$

Add \frac{27}{4} and 7 to get \frac{55}{4}.

$$\frac{169}{16}-\left(-\frac{1}{4}\times \frac{55}{4}\right)=2$$

Multiply -\frac{1}{4} and \frac{55}{4} to get -\frac{55}{16}.

$$\frac{169}{16}-\left(-\frac{55}{16}\right)=2$$

The opposite of -\frac{55}{16} is \frac{55}{16}.

$$\frac{169}{16}+\frac{55}{16}=2$$

Add \frac{169}{16} and \frac{55}{16} to get 14.

$$14=2$$

Compare 14 and 2.

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