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\left(2-3\sqrt{3}\right)^{2}
Multiply 2-3\sqrt{3} and 2-3\sqrt{3} to get \left(2-3\sqrt{3}\right)^{2}.
4-12\sqrt{3}+9\left(\sqrt{3}\right)^{2}
Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(2-3\sqrt{3}\right)^{2}.
4-12\sqrt{3}+9\times 3
The square of \sqrt{3} is 3.
4-12\sqrt{3}+27
Multiply 9 and 3 to get 27.
31-12\sqrt{3}
Add 4 and 27 to get 31.