Solve (2-3/4*4/5)=(1/12+4/15)

$$( 2 - \frac { 3 } { 4 } \times \frac { 4 } { 5 } ) = ( \frac { 1 } { 12 } + \frac { 4 } { 15 } )$$

Verify

Solution Steps

Multiply \frac{3}{4} times \frac{4}{5} by multiplying numerator times numerator and denominator times denominator.

$$2-\frac{3\times 4}{4\times 5}=\frac{1}{12}+\frac{4}{15}$$

Cancel out 4 in both numerator and denominator.

$$2-\frac{3}{5}=\frac{1}{12}+\frac{4}{15}$$

Convert 2 to fraction \frac{10}{5}.

$$\frac{10}{5}-\frac{3}{5}=\frac{1}{12}+\frac{4}{15}$$

Since \frac{10}{5} and \frac{3}{5} have the same denominator, subtract them by subtracting their numerators.

$$\frac{10-3}{5}=\frac{1}{12}+\frac{4}{15}$$

Subtract 3 from 10 to get 7.

$$\frac{7}{5}=\frac{1}{12}+\frac{4}{15}$$

Least common multiple of 12 and 15 is 60. Convert \frac{1}{12} and \frac{4}{15} to fractions with denominator 60.

$$\frac{7}{5}=\frac{5}{60}+\frac{16}{60}$$

Since \frac{5}{60} and \frac{16}{60} have the same denominator, add them by adding their numerators.

$$\frac{7}{5}=\frac{5+16}{60}$$

Add 5 and 16 to get 21.

$$\frac{7}{5}=\frac{21}{60}$$

Reduce the fraction \frac{21}{60} to lowest terms by extracting and canceling out 3.

$$\frac{7}{5}=\frac{7}{20}$$

Least common multiple of 5 and 20 is 20. Convert \frac{7}{5} and \frac{7}{20} to fractions with denominator 20.

$$\frac{28}{20}=\frac{7}{20}$$

Compare \frac{28}{20} and \frac{7}{20}.

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