Solve (2-2/3)*(2/3+2)^2

$$( 2 - \frac { 2 } { 3 } ) \times ( \frac { 2 } { 3 } + 2 ) ^ { 2 }$$

Evaluate

$$\frac{256}{27}\approx 9.481481481$$

Solution Steps

Subtract \frac{2}{3} from 2 to get \frac{4}{3}.

$$\frac{4}{3}\left(\frac{2}{3}+2\right)^{2}$$

Add \frac{2}{3} and 2 to get \frac{8}{3}.

$$\frac{4}{3}\times \left(\frac{8}{3}\right)^{2}$$

Calculate \frac{8}{3} to the power of 2 and get \frac{64}{9}.

$$\frac{4}{3}\times \frac{64}{9}$$

Multiply \frac{4}{3} and \frac{64}{9} to get \frac{256}{27}.

$$\frac{256}{27}$$

Factor

$$\frac{2 ^ {8}}{3 ^ {3}} = 9\frac{13}{27} = 9.481481481481481$$