Solve for f
f=-\frac{x^{3}}{2}+x+\frac{3}{2x}
x\neq 0
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2xf=3+2x^{2}-x^{4}
The equation is in standard form.
\frac{2xf}{2x}=-\frac{\left(x^{2}-3\right)\left(x^{2}+1\right)}{2x}
Divide both sides by 2x.
f=-\frac{\left(x^{2}-3\right)\left(x^{2}+1\right)}{2x}
Dividing by 2x undoes the multiplication by 2x.
f=-\frac{x^{3}}{2}+x+\frac{3}{2x}
Divide -\left(-3+x^{2}\right)\left(1+x^{2}\right) by 2x.
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