Solve (2)62x+3x+1+2x

$$( 2 ) 62 x + 3 x + 1 + 2 x$$

Evaluate

$$129x+1$$

Solution Steps

Multiply 2 and 62 to get 124.

$$124x+3x+1+2x$$

Combine 124x and 3x to get 127x.

$$127x+1+2x$$

Combine 127x and 2x to get 129x.

$$129x+1$$

Differentiate w.r.t. x

$$129$$

Steps Using Derivative Rule for Sum

Multiply 2 and 62 to get 124.

$$\frac{\mathrm{d}}{\mathrm{d}x}(124x+3x+1+2x)$$

Combine 124x and 3x to get 127x.

$$\frac{\mathrm{d}}{\mathrm{d}x}(127x+1+2x)$$

Combine 127x and 2x to get 129x.

$$\frac{\mathrm{d}}{\mathrm{d}x}(129x+1)$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is 0. The derivative of ax^{n} is nax^{n-1}.

$$129x^{1-1}$$

Subtract 1 from 1.

$$129x^{0}$$

For any term t except 0, t^{0}=1.

$$129\times 1$$

For any term t, t\times 1=t and 1t=t.

$$129$$