Solve (2)6div4^-1+((-12)-(-2)+2)=

$$( 2 ) 6 \div 4 ^ { - 1 } + ( ( - 12 ) - ( - 2 ) + 2 ) =$$

Evaluate

$$40$$

Solution Steps

Multiply 2 and 6 to get 12.

$$\frac{12}{4^{-1}}+-12-\left(-2\right)+2$$

Calculate 4 to the power of -1 and get \frac{1}{4}.

$$\frac{12}{\frac{1}{4}}+-12-\left(-2\right)+2$$

Divide 12 by \frac{1}{4} by multiplying 12 by the reciprocal of \frac{1}{4}.

$$12\times 4+-12-\left(-2\right)+2$$

Multiply 12 and 4 to get 48.

$$48+-12-\left(-2\right)+2$$

The opposite of -2 is 2.

$$48-12+2+2$$

Add -12 and 2 to get -10.

$$48-10+2$$

Subtract 10 from 48 to get 38.

$$38+2$$

Add 38 and 2 to get 40.

$$40$$

Factor

$$2^{3}\times 5$$