Solve (2)-2^2div|6-10|-3*(-1)^2019

$$( 2 ) - 2 ^ { 2 } \div | 6 - 10 | - 3 \times ( - 1 ) ^ { 2019 }$$

Evaluate

$$4$$

Solution Steps

Calculate 2 to the power of 2 and get 4.

$$2-\frac{4}{|6-10|}-3\left(-1\right)^{2019}$$

Subtract 10 from 6 to get -4.

$$2-\frac{4}{|-4|}-3\left(-1\right)^{2019}$$

The absolute value of a real number a is a when a\geq 0, or -a when a<0. The absolute value of -4 is 4.

$$2-\frac{4}{4}-3\left(-1\right)^{2019}$$

Divide 4 by 4 to get 1.

$$2-1-3\left(-1\right)^{2019}$$

Subtract 1 from 2 to get 1.

$$1-3\left(-1\right)^{2019}$$

Calculate -1 to the power of 2019 and get -1.

$$1-3\left(-1\right)$$

Multiply 3 and -1 to get -3.

$$1-\left(-3\right)$$

The opposite of -3 is 3.

$$1+3$$

Add 1 and 3 to get 4.

$$4$$

Factor

$$2^{2}$$