Solve (2)(03x^{3}y^{4})^2*(02x^4y^3)^2

$$( 2 ) ( 03 x ^ { 3 } y ^ { 4 } ) ^ { 2 } \cdot ( 02 x ^ { 4 } y ^ { 3 } ) ^ { 2 }$$

Evaluate

$$0$$

Solution Steps

Multiply 0 and 3 to get 0.

$$2\times \left(0x^{3}y^{4}\right)^{2}\times \left(0\times 2x^{4}y^{3}\right)^{2}$$

Anything times zero gives zero.

$$2\times 0^{2}\times \left(0\times 2x^{4}y^{3}\right)^{2}$$

Calculate 0 to the power of 2 and get 0.

$$2\times 0\times \left(0\times 2x^{4}y^{3}\right)^{2}$$

Multiply 2 and 0 to get 0.

$$0\times \left(0\times 2x^{4}y^{3}\right)^{2}$$

Multiply 0 and 2 to get 0.

$$0\times \left(0x^{4}y^{3}\right)^{2}$$

Anything times zero gives zero.

$$0\times 0^{2}$$

Calculate 0 to the power of 2 and get 0.

$$0\times 0$$

Multiply 0 and 0 to get 0.

$$0$$

Factor

$$0$$