Solve (2)(-5)^3-3*(-1/2)^4

$$( 2 ) ( - 5 ) ^ { 3 } - 3 \times ( - \frac { 1 } { 2 } ) ^ { 4 }$$

Evaluate

$$-\frac{4003}{16}=-250.1875$$

Solution Steps

Calculate -5 to the power of 3 and get -125.

$$2\left(-125\right)-3\left(-\frac{1}{2}\right)^{4}$$

Multiply 2 and -125 to get -250.

$$-250-3\left(-\frac{1}{2}\right)^{4}$$

Calculate -\frac{1}{2} to the power of 4 and get \frac{1}{16}.

$$-250-3\times \frac{1}{16}$$

Multiply 3 and \frac{1}{16} to get \frac{3}{16}.

$$-250-\frac{3}{16}$$

Convert -250 to fraction -\frac{4000}{16}.

$$-\frac{4000}{16}-\frac{3}{16}$$

Since -\frac{4000}{16} and \frac{3}{16} have the same denominator, subtract them by subtracting their numerators.

$$\frac{-4000-3}{16}$$

Subtract 3 from -4000 to get -4003.

$$-\frac{4003}{16}$$

Factor

$$-\frac{4003}{16} = -250\frac{3}{16} = -250.1875$$