Solve (2)(-1)^10+(-2)^3div4+(-2^2)-|-7|

$$( 2 ) ( - 1 ) ^ { 10 } + ( - 2 ) ^ { 3 } \div 4 + ( - 2 ^ { 2 } ) - | - 7 |$$

Evaluate

$$-11$$

Solution Steps

Calculate -1 to the power of 10 and get 1.

$$2\times 1+\frac{\left(-2\right)^{3}}{4}-2^{2}-|-7|$$

Multiply 2 and 1 to get 2.

$$2+\frac{\left(-2\right)^{3}}{4}-2^{2}-|-7|$$

Calculate -2 to the power of 3 and get -8.

$$2+\frac{-8}{4}-2^{2}-|-7|$$

Divide -8 by 4 to get -2.

$$2-2-2^{2}-|-7|$$

Subtract 2 from 2 to get 0.

$$-2^{2}-|-7|$$

Calculate 2 to the power of 2 and get 4.

$$-4-|-7|$$

The absolute value of a real number a is a when a\geq 0, or -a when a<0. The absolute value of -7 is 7.

$$-4-7$$

Subtract 7 from -4 to get -11.

$$-11$$

Factor

$$-11$$