Solve (2)^2-4(1)(-2k-2)=0

$$( 2 ) ^ { 2 } - 4 ( 1 ) ( - 2 k - 2 ) = 0$$

Solve for k

$$k = -\frac{3}{2} = -1\frac{1}{2} = -1.5$$

Steps for Solving Linear Equation

Calculate 2 to the power of 2 and get 4.

$$4-4\times 1\left(-2k-2\right)=0$$

Multiply 4 and 1 to get 4.

$$4-4\left(-2k-2\right)=0$$

Use the distributive property to multiply -4 by -2k-2.

$$4+8k+8=0$$

Add 4 and 8 to get 12.

$$12+8k=0$$

Subtract 12 from both sides. Anything subtracted from zero gives its negation.

$$8k=-12$$

Divide both sides by 8.

$$k=\frac{-12}{8}$$

Reduce the fraction \frac{-12}{8} to lowest terms by extracting and canceling out 4.

$$k=-\frac{3}{2}$$