Solve (2(4n))+(4n-3)=t_{n}

$$( 2 ( 4 n ) ) + ( 4 n - 3 ) = t _ { n }$$

Solve for n

$$n=\frac{t_{n}+3}{12}$$

Steps for Solving Linear Equation

Multiply 2 and 4 to get 8.

$$8n+4n-3=t_{n}$$

Combine 8n and 4n to get 12n.

$$12n-3=t_{n}$$

Add 3 to both sides.

$$12n=t_{n}+3$$

Divide both sides by 12.

$$\frac{12n}{12}=\frac{t_{n}+3}{12}$$

Dividing by 12 undoes the multiplication by 12.

$$n=\frac{t_{n}+3}{12}$$

Divide t_{n}+3 by 12.

$$n=\frac{t_{n}}{12}+\frac{1}{4}$$

Solve for t_n

$$t_{n}=12n-3$$

Solution Steps

Multiply 2 and 4 to get 8.

$$8n+4n-3=t_{n}$$

Combine 8n and 4n to get 12n.

$$12n-3=t_{n}$$

Swap sides so that all variable terms are on the left hand side.

$$t_{n}=12n-3$$