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4\left(\sqrt{7}\right)^{2}+16\sqrt{7}+16
Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(2\sqrt{7}+4\right)^{2}.
4\times 7+16\sqrt{7}+16
The square of \sqrt{7} is 7.
28+16\sqrt{7}+16
Multiply 4 and 7 to get 28.
44+16\sqrt{7}
Add 28 and 16 to get 44.
4\left(\sqrt{7}\right)^{2}+16\sqrt{7}+16
Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(2\sqrt{7}+4\right)^{2}.
4\times 7+16\sqrt{7}+16
The square of \sqrt{7} is 7.
28+16\sqrt{7}+16
Multiply 4 and 7 to get 28.
44+16\sqrt{7}
Add 28 and 16 to get 44.