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\left(2\sqrt{5}\right)^{2}-3^{2}
Multiplication can be transformed into difference of squares using the rule: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.
2^{2}\left(\sqrt{5}\right)^{2}-3^{2}
Expand \left(2\sqrt{5}\right)^{2}.
4\left(\sqrt{5}\right)^{2}-3^{2}
Calculate 2 to the power of 2 and get 4.
4\times 5-3^{2}
The square of \sqrt{5} is 5.
20-3^{2}
Multiply 4 and 5 to get 20.
20-9
Calculate 3 to the power of 2 and get 9.
11
Subtract 9 from 20 to get 11.