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2\left(\sqrt{3}\right)^{2}+4\sqrt{3}-\sqrt{3}-2
Apply the distributive property by multiplying each term of 2\sqrt{3}-1 by each term of \sqrt{3}+2.
2\times 3+4\sqrt{3}-\sqrt{3}-2
The square of \sqrt{3} is 3.
6+4\sqrt{3}-\sqrt{3}-2
Multiply 2 and 3 to get 6.
6+3\sqrt{3}-2
Combine 4\sqrt{3} and -\sqrt{3} to get 3\sqrt{3}.
4+3\sqrt{3}
Subtract 2 from 6 to get 4.