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6\left(\sqrt{3}\right)^{2}-4\sqrt{3}+12\sqrt{3}-8
Apply the distributive property by multiplying each term of 2\sqrt{3}+4 by each term of 3\sqrt{3}-2.
6\times 3-4\sqrt{3}+12\sqrt{3}-8
The square of \sqrt{3} is 3.
18-4\sqrt{3}+12\sqrt{3}-8
Multiply 6 and 3 to get 18.
18+8\sqrt{3}-8
Combine -4\sqrt{3} and 12\sqrt{3} to get 8\sqrt{3}.
10+8\sqrt{3}
Subtract 8 from 18 to get 10.