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6\sqrt{3}-2\left(\sqrt{3}\right)^{2}+9-3\sqrt{3}
Apply the distributive property by multiplying each term of 2\sqrt{3}+3 by each term of 3-\sqrt{3}.
6\sqrt{3}-2\times 3+9-3\sqrt{3}
The square of \sqrt{3} is 3.
6\sqrt{3}-6+9-3\sqrt{3}
Multiply -2 and 3 to get -6.
6\sqrt{3}+3-3\sqrt{3}
Add -6 and 9 to get 3.
3\sqrt{3}+3
Combine 6\sqrt{3} and -3\sqrt{3} to get 3\sqrt{3}.