Solve (27/5-5/8)*6/15

$$( 2 \frac { 7 } { 5 } - \frac { 5 } { 8 } ) \times \frac { 6 } { 15 }$$

Evaluate

$$\frac{111}{100}=1.11$$

Solution Steps

Multiply 2 and 5 to get 10.

$$\left(\frac{10+7}{5}-\frac{5}{8}\right)\times \frac{6}{15}$$

Add 10 and 7 to get 17.

$$\left(\frac{17}{5}-\frac{5}{8}\right)\times \frac{6}{15}$$

Least common multiple of 5 and 8 is 40. Convert \frac{17}{5} and \frac{5}{8} to fractions with denominator 40.

$$\left(\frac{136}{40}-\frac{25}{40}\right)\times \frac{6}{15}$$

Since \frac{136}{40} and \frac{25}{40} have the same denominator, subtract them by subtracting their numerators.

$$\frac{136-25}{40}\times \frac{6}{15}$$

Subtract 25 from 136 to get 111.

$$\frac{111}{40}\times \frac{6}{15}$$

Reduce the fraction \frac{6}{15} to lowest terms by extracting and canceling out 3.

$$\frac{111}{40}\times \frac{2}{5}$$

Multiply \frac{111}{40} times \frac{2}{5} by multiplying numerator times numerator and denominator times denominator.

$$\frac{111\times 2}{40\times 5}$$

Do the multiplications in the fraction \frac{111\times 2}{40\times 5}.

$$\frac{222}{200}$$

Reduce the fraction \frac{222}{200} to lowest terms by extracting and canceling out 2.

$$\frac{111}{100}$$

Factor

$$\frac{3 \cdot 37}{2 ^ {2} \cdot 5 ^ {2}} = 1\frac{11}{100} = 1.11$$