Solve (24/7-1,2)*55/6

$$( 2 \frac { 4 } { 7 } - 1,2 ) \cdot 5 \frac { 5 } { 6 }$$

Evaluate

$$8$$

Solution Steps

Multiply 2 and 7 to get 14.

$$\left(\frac{14+4}{7}-1,2\right)\times \frac{5\times 6+5}{6}$$

Add 14 and 4 to get 18.

$$\left(\frac{18}{7}-1,2\right)\times \frac{5\times 6+5}{6}$$

Convert decimal number 1,2 to fraction \frac{12}{10}. Reduce the fraction \frac{12}{10} to lowest terms by extracting and canceling out 2.

$$\left(\frac{18}{7}-\frac{6}{5}\right)\times \frac{5\times 6+5}{6}$$

Least common multiple of 7 and 5 is 35. Convert \frac{18}{7} and \frac{6}{5} to fractions with denominator 35.

$$\left(\frac{90}{35}-\frac{42}{35}\right)\times \frac{5\times 6+5}{6}$$

Since \frac{90}{35} and \frac{42}{35} have the same denominator, subtract them by subtracting their numerators.

$$\frac{90-42}{35}\times \frac{5\times 6+5}{6}$$

Subtract 42 from 90 to get 48.

$$\frac{48}{35}\times \frac{5\times 6+5}{6}$$

Multiply 5 and 6 to get 30.

$$\frac{48}{35}\times \frac{30+5}{6}$$

Add 30 and 5 to get 35.

$$\frac{48}{35}\times \frac{35}{6}$$

Multiply \frac{48}{35} times \frac{35}{6} by multiplying numerator times numerator and denominator times denominator.

$$\frac{48\times 35}{35\times 6}$$

Cancel out 35 in both numerator and denominator.

$$\frac{48}{6}$$

Divide 48 by 6 to get 8.

$$8$$

Factor

$$2^{3}$$