Solve (24/3+6/3)-6/3

$$( 2 \frac { 4 } { 3 } + \frac { 6 } { 3 } ) - \frac { 6 } { 3 }$$

Evaluate

$$\frac{10}{3}\approx 3.333333333$$

Solution Steps

Multiply 2 and 3 to get 6.

$$\frac{6+4}{3}+\frac{6}{3}-\frac{6}{3}$$

Add 6 and 4 to get 10.

$$\frac{10}{3}+\frac{6}{3}-\frac{6}{3}$$

Since \frac{10}{3} and \frac{6}{3} have the same denominator, add them by adding their numerators.

$$\frac{10+6}{3}-\frac{6}{3}$$

Add 10 and 6 to get 16.

$$\frac{16}{3}-\frac{6}{3}$$

Since \frac{16}{3} and \frac{6}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{16-6}{3}$$

Subtract 6 from 16 to get 10.

$$\frac{10}{3}$$

Factor

$$\frac{2 \cdot 5}{3} = 3\frac{1}{3} = 3.3333333333333335$$