Solve (23/4-3/4)div11/3

$$( 2 \frac { 3 } { 4 } - \frac { 3 } { 4 } ) \div 1 \frac { 1 } { 3 }$$

Evaluate

$$\frac{3}{2}=1.5$$

Solution Steps

Multiply 2 and 4 to get 8.

$$\frac{\frac{8+3}{4}-\frac{3}{4}}{\frac{1\times 3+1}{3}}$$

Add 8 and 3 to get 11.

$$\frac{\frac{11}{4}-\frac{3}{4}}{\frac{1\times 3+1}{3}}$$

Since \frac{11}{4} and \frac{3}{4} have the same denominator, subtract them by subtracting their numerators.

$$\frac{\frac{11-3}{4}}{\frac{1\times 3+1}{3}}$$

Subtract 3 from 11 to get 8.

$$\frac{\frac{8}{4}}{\frac{1\times 3+1}{3}}$$

Divide 8 by 4 to get 2.

$$\frac{2}{\frac{1\times 3+1}{3}}$$

Multiply 1 and 3 to get 3.

$$\frac{2}{\frac{3+1}{3}}$$

Add 3 and 1 to get 4.

$$\frac{2}{\frac{4}{3}}$$

Divide 2 by \frac{4}{3} by multiplying 2 by the reciprocal of \frac{4}{3}.

$$2\times \frac{3}{4}$$

Express 2\times \frac{3}{4} as a single fraction.

$$\frac{2\times 3}{4}$$

Multiply 2 and 3 to get 6.

$$\frac{6}{4}$$

Reduce the fraction \frac{6}{4} to lowest terms by extracting and canceling out 2.

$$\frac{3}{2}$$

Factor

$$\frac{3}{2} = 1\frac{1}{2} = 1.5$$