Solve (23/4+21/5)16

$$( 2 \frac { 3 } { 4 } + 2 \frac { 1 } { 5 } ) 16$$

Evaluate

$$\frac{396}{5}=79.2$$

Solution Steps

Multiply 2 and 4 to get 8.

$$\left(\frac{8+3}{4}+\frac{2\times 5+1}{5}\right)\times 16$$

Add 8 and 3 to get 11.

$$\left(\frac{11}{4}+\frac{2\times 5+1}{5}\right)\times 16$$

Multiply 2 and 5 to get 10.

$$\left(\frac{11}{4}+\frac{10+1}{5}\right)\times 16$$

Add 10 and 1 to get 11.

$$\left(\frac{11}{4}+\frac{11}{5}\right)\times 16$$

Least common multiple of 4 and 5 is 20. Convert \frac{11}{4} and \frac{11}{5} to fractions with denominator 20.

$$\left(\frac{55}{20}+\frac{44}{20}\right)\times 16$$

Since \frac{55}{20} and \frac{44}{20} have the same denominator, add them by adding their numerators.

$$\frac{55+44}{20}\times 16$$

Add 55 and 44 to get 99.

$$\frac{99}{20}\times 16$$

Express \frac{99}{20}\times 16 as a single fraction.

$$\frac{99\times 16}{20}$$

Multiply 99 and 16 to get 1584.

$$\frac{1584}{20}$$

Reduce the fraction \frac{1584}{20} to lowest terms by extracting and canceling out 4.

$$\frac{396}{5}$$

Factor

$$\frac{2 ^ {2} \cdot 3 ^ {2} \cdot 11}{5} = 79\frac{1}{5} = 79.2$$